So here we are given that the the velocity of the proton ( V ) is 2.0 × [tex]10^6[/tex] meters / second, with a magnetic field of strength 5.5 × [tex]10^{-3}[/tex] tesla. If they each form a right angle, they are hence perpendicular to one another, such that ....
F = q( V × B ),
F = q v B( sin ∅ ),
F = q v B( sin( 90 ) )
.... they form the following formula. Let's go through each of the variables in our formula here -
{ F = Magnetic Force ( which has to be calculated ), q = charge of proton (has charge of 1.602 × [tex]10^{19}[/tex] coulombs ), B = magnetic field }
All we have to do now is plug and chug,
F = ( 1.602 × [tex]10^{19}[/tex] )( 2.0 × [tex]10^6[/tex] )( 5.5 × [tex]10^{-3}[/tex] ) = ( About ) 1.8 × [tex]10^{-15}[/tex] Newtons
Answer: hey there, the answer to your question is (E)
Explanation:
