Answer:
0.897
Step-by-step explanation:
Brahmagupta formula for quadratic equation [tex]ax^2+bx=c[/tex] is
[tex]x=\dfrac{\sqrt{4ac+b^2}-b}{2a}[/tex]
It involved only one solution.
The given equation is
[tex]3x^2+4x=6[/tex]
Here, a=3, b=4 and c=6. Put these values in the above formula.
[tex]x=\dfrac{\sqrt{4(3)(6)+(4)^2}-4}{2(3)}[/tex]
[tex]x=\dfrac{\sqrt{4(3)(6)+(4)^2}-4}{2(3)}[/tex]
[tex]x=\dfrac{\sqrt{72+16}-4}{6}[/tex]
[tex]x=\dfrac{\sqrt{88}-4}{6}[/tex]
[tex]x\approx \dfrac{5.38}{6}[/tex]
[tex]x\approx 0.897[/tex]
Therefore, the required solution is 0.897.
