Respuesta :
Answer:
Explanation:
Zn(s) + Cu⁺( aq) ⇒ Zn⁺²( aq ) + Cu(s)
In oxidation reaction of an element or ion , the oxidation number is increased . Oxidation no is total charge on the atom or ion
In the following half reaction Zn(s) is oxidised to Zn⁺²
Zn( s ) ⇒ Zn⁺²(aq) + 2e⁻
In this reaction charge on Zn(s) is zero
After reaction charge on formed Zn⁺² is +2 . Hence there is increase in oxidation number from 0 to + 2 . Hence Zn(s) is oxidised to Zn⁺² ion .
