Total depth of the bottom of the plate is 4 + 1 = 5
Force = limit(5,1) 62.5 *7* x * dx
= 437.5. Lim(5,1) x*dx
= 437.5(x^2/2)^5 , 1
= 437.5 x (5^2/2 - 1/2)
= 437.5 x 12
= 5,250 pounds
The hydrostatic force against one side of the plate will be 5250 pounds.
The force exerted by the water of surface is known as hydrostatic force.
A 4-ft-high and 7-ft-wide rectangular plate is submerged vertically in water so that the top is 1 ft below the surface.
[tex]\rm Force = \int^5_1 62.5 *7* x * dx\\\\\\ Force = 437.5 \left [ \dfrac{x^2}{2} \right]^5_1\\\\\\Force = 218.75 \left [ x^2 \right]^5_1\\\\[/tex]
Solve the equation further, we have
Force = 218.75 x (5² – 1²)
Force = 218.75 x 24
Force = 5,250 pounds
More about the hydrostatic force link is given below.
https://brainly.com/question/14838087
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