Could someone answer the question with the photo linked below? Then explain how to solve it?

Answer:
Hey there!
Pythagorean Theorem:
[tex]a^2+b^2=c^2\\[/tex]
Let 6 be a, and 11 be b.
[tex]6^2+11^2=c^2\\[/tex]
[tex]36+121=c^2\\[/tex]
[tex]157=c^2[/tex]
[tex]\sqrt{157} =c[/tex]
Hope this helps :)
Answer:
[tex]12.529[/tex]
Step-by-step explanation:
[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {6}^{2} + {11}^{2} = {c}^{2} \\ 36 + 121 = {c}^{2} \\ 157 = {c}^{2} \\ \sqrt{157} = {c}^{2} \\ c = 12.529[/tex]
[tex]hope \: it \: helps \: < 3[/tex]