Answer:
Option (4)
Step-by-step explanation:
Surface area of a prism = 2B + P×h
where B = Area of the triangular base
P = perimeter of the triangular base
h = height of the prism
B = [tex]\frac{1}{2}(\text{leg 1})(\text{leg 2})[/tex]
Since, (Hypotenuse)² + (Leg 1)² + (Leg 2)² [Pythagoras theorem]
(20)² = (12)² + (Leg 2)²
Leg 2 = [tex]\sqrt{400-144}[/tex]
= 16 units
Therefore, B = [tex]\frac{1}{2}\times 12\times 16[/tex]
= 96 units²
P = 12 + 16 + 20
P = 48 units
h = 7.5 units
Surface area of the prism = 2(96) + (48×7.5)
= 192 + 360
= 552 units²
Therefore, surface area of the given triangular prism = 552 units²
Option (4) will be the answer.
