Answer:
(C)[tex]6t^2+5[/tex]
Step-by-step explanation:
Given the distance, d(t) of a particle moving in a straight line at any time t is:
[tex]d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.[/tex]
To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).
[tex]v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5[/tex]
The correct option is C.
