given the equation below which of the following shows the quadratic formula correctly applied? 3x^2-4x-12=0

[tex] {3x}^{2} - 4x - 12 = 0[/tex]
[tex]a = 3[/tex]
[tex]b = - 4[/tex]
[tex]c = - 12[/tex]
Formula:
[tex] \boxed{x = \dfrac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }[/tex]
Replacing:
[tex]x = \dfrac{ -( - 4) \pm \sqrt{ { (- 4)}^{2} - 4(3)( - 12)} }{2(3)} [/tex]
Option: C).