Answer:
The sequence diverges ( B )
Explanation:
[tex]\frac{n^{16} }{(In n)^{32} }[/tex]
Applying the Growth rates of sequences theorem to find the limit of the given sequence above
[tex]\lim_{n \to \infty} \frac{n^{16} }{(In n)^{32} }[/tex] = ∞ this means that
The sequence is divergent because the rate at which n increase is very much higher than the rate at which (In n) increases