Respuesta :
Answer: Mass of methyl 4-fluoro-3-nitrobenzoate = 199 mg;
Mass of 4-chlorobenzylamine = 282 mg
Explanation: The mass and mol of a molecule is related by its molar mass, which is given in g/mol.
The molar mass of methyl 4-fluoro-3-nitrobenzoate, which has molecular formula: [tex]C_{8}H_{6}FNO_{4}[/tex] is:
[tex]C_{8}H_{6}FNO_{4}[/tex] = 12.8 + 6.1 + 19 + 14 + 16.4 = 199 g/mol
Since it is asking in mg: MM = 199.10³mg/mol
For 4-chlorobenzylamine, with molecular formula [tex]C_{7}H_{8}ClN[/tex]:
[tex]C_{7}H_{8}ClN[/tex] = 12.7 + 8.1 + 35 + 14 = 141 g/mol
In mg: MM = 141.10³mg/mol
The reaction requires 1 mmol of [tex]C_{8}H_{6}FNO_{4}[/tex] , then its mass is:
m = 1.10⁻³ mol * 199.10³mg/mol = 199 mg
For [tex]C_{7}H_{8}ClN[/tex], it requires 2mmol:
m = 2.10⁻³ mol * 141.10³ mg/mol = 282 mg
For the SNAr reaction, it is necessary 199 mg of methyl 4-fluoro-3-nitrobenzoate and 282 mg of 4-chlorobenzylamine
The mass of 1 mmol methyl 4-fluoro-3-nitrobenzoate is 199.14 mg and the mass of 2 mmol of 4-chlorobenzyl amine is 283.2 mg
To determine the masses of both reagents,
First we will determine their molar masses
- For methyl 4-fluoro-3-nitrobenzoate (C₈H₆FNO₄)
Molar mass = 199.14 g/mol
Now, for the mass of 1 mmol of methyl 4-fluoro-3-nitrobenzoate
Using the formula
Mass = Number of moles × Molar mass
Mass = 1 mmol × 199.14 g/mol
Mass = 199.14 mg
- For 4-chlorobenzyl amine (C₇H₈ClN)
Molar mass = 141.6 g/mol
Now, for the mass of 2 mmol of 4-chlorobenzyl amine
Mass = 2 mmol × 141.6 g/mol
Mass = 283.2 mg
Hence, the mass of 1 mmol methyl 4-fluoro-3-nitrobenzoate is 199.14 mg and the mass of 2 mmol of 4-chlorobenzyl amine is 283.2 mg
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