Answer:
Q.2 [tex]4\sqrt2[/tex] units
Q.3 [tex]10\sqrt2[/tex] units
Step-by-step explanation:
Given that points:
C(-1, 3) and D (-5, 7)
E(0, -5) and F(10, -15)
To find:
Q.2. Distance between C and D
Q.3. Distance between E and F
Solution:
First of all, let us solve the question marked as number 2 in the attached image.
C(-1, 3) and D (-5, 7)
[tex]x_2 = -5\\x_1 = -1\\y_2 = 7\\y_1 = 3[/tex]
To find the distance 'd' between the points, we can use distance formula:
[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d = \sqrt{(-5-(-1))^2+(7-3)^2}\\\Rightarrow d = \sqrt{(-4)^2+(4)^2}\\\Rightarrow d =\sqrt{16+16}\\\Rightarrow d =\sqrt{32} = 4\sqrt2\ units[/tex]
First of all, let us solve the question marked as number 3 in the attached image.
E(0, -5) and F(10, -15)
[tex]x_2 = 10\\x_1 = 0\\y_2 = -15\\y_1 = -5[/tex]
To find the distance 'd' between the points, we can use distance formula:
[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d = \sqrt{(10-0)^2+(-15-(-5))^2}\\\Rightarrow d = \sqrt{10^2+(-10)^2}\\\Rightarrow d =\sqrt{100+100}\\\Rightarrow d =\sqrt{200} = 10\sqrt2\ units[/tex]
Please find attached image for the answers filled in the boxes.
