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The chemical formula for barium oxide is BaO. A chemist determined by measurements that 0.065 moles of barium oxide participate in a chemical reaction. Calculate the mass of barium oxide that participates.

Respuesta :

Answer:

9.97 g (corrected to 3 significant figures.)

Explanation:

mass = no. of moles x molar mass

Atomic mass of Barium = 137.327; oxygen = 15.999,

so the molar mass of BaO = 137.327 + 15.999

=153.326

Hence, the mass is

0.065 x 153.326

=9.97 g (corrected to 3 significant figures.)

Answer:

9,97 g to the nearest hundredth.

Explanation:

Using the relative atomic masses of Barium and Oxygen:

1 mole of BaO has a mass of 137.327 + 16 = 153.327 g.

So 0.065 moles has a mass of 153.327 * 0.065

= 9.966 g.

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