Answer:
[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]
The maximum amount of sand that can be stored in this structure is 1675.52 m³.
Step-by-step explanation:
The volume of a conical-shaped structure is given by
[tex]V = \frac{1}{3} (\pi \cdot r^2 \cdot h)[/tex]
Where r is the radius and h is the height of the structure.
We are given that
radius = 10m
height = 16m
Substituting the above values into the formula, we get
[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]
Therefore, the maximum amount of sand th can be stored in this structure is 1675.52 m³.
