danielsan142
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Determine all numbers at which are function Continuous..
f(x)={
x^2 + 5x - 36/
x^2 + 8x - 9
if x≠-9
if x= -9}
a.
continuous at every real number except x = 1 and x = -9
b. continuous at every real number except x = -9
c.continuous at every real number except x = 1
d. continuous at every real number except x = -9 and x = 4

Determine all numbers at which are function Continuous fx x2 5x 36 x2 8x 9 if x9 if x 9 a continuous at every real number except x 1 and x 9 b continuous at eve class=

Respuesta :

Answer:

For this case we have this function:

[tex] f(x) =\frac{x^2 +5x-36}{x^2 +8x-9}, x=9[/tex]

We can factor the denominator and we got:

[tex] f(x) =\frac{x^2 +5x-36}{(x+9)(x-1)}, x=9[/tex]

And since we can't divide by 0 then the value of x can't be 1 or -9 so then the best answer for this case would be:

Continuous at every real number except x=1 and x=-9

Step-by-step explanation:

For this case we have this function:

[tex] f(x) =\frac{x^2 +5x-36}{x^2 +8x-9}, x=9[/tex]

We can factor the denominator and we got:

[tex] f(x) =\frac{x^2 +5x-36}{(x+9)(x-1)}, x=9[/tex]

And since we can't divide by 0 then the value of x can't be 1 or -9 so then the best answer for this case would be:

Continuous at every real number except x=1 and x=-9

Answer:

The answer is C.

Step-by-step explanation:

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