contestada

. The four metals, Strontium(Sr), Francium (Fr), Yttrium (Y), and Europium (Eu), in separate experiments, are dipped in aqueous solutions of SrNO3, FrNO3, Y(NO3)3, and Eu(NO3)2. The following results are obtained: 1. Yttrium metal does not react with any of the solutions 2. Strontium metal reacts with all of the other metals solutions 3. Francium metal reacts in a solution of Eu(NO3)2 a) List the four oxidizing agents in order from strongest to weakest by creating a small reduction table. Explain your reasoning below b) List the four reducing agents in order from strongest to weakest

Respuesta :

znk

Answer:

a) Y³⁺ > Eu²⁺ > Fr⁺ > Sr²⁺

b) Sr > Fr > Eu > Y

Explanation:

Y is the least reactive metal because it does not react with any of the other solutions.

Sr is the most reactive metal because it reacts with all of the other solutions.  

Sr + 2Fr⁺ ⟶Sr²⁺ + 2Fr

3Sr + 2Y³⁺ ⟶ 2Sr²⁺ + 2Y

Sr + Eu²⁺ ⟶ Sr²⁺ + Eu

Fr is more reactive than Eu because it reacts with Eu(NO₃)₂.

2Fr + Eu²⁺ ⟶ 2Fr⁺ + Eu

The order of reactivity is

Sr > Fr > Eu > Y

b) Reducing agents

In each of the above reactions. the more reactive metal is acting as a reducing agent — it is donating electrons to the cation of the other metal.

Thus, the order of activity of reducing agents is

Sr > Fr > Eu > Y

a) Oxidizing agents

The metal cations are the oxidizing agents.

The order of reactivity of the oxidizing agents is the reverse order of the reducing agents

Y³⁺ > Eu²⁺ > Fr⁺ > Sr²⁺

c) Standard reduction potential table

See the image below.

 

Ver imagen znk

Otras preguntas