Tessa solves the equation below by first squaring both sides of the equation HELP PLEASE

Answer:
Step-by-step explanation:
[tex] \sqrt{ {x}^{2} - 3x - 6} = x - 1[/tex]
Squaring on both sides:
[tex] {x}^{2} - 3x - 6 = {(x - 1)}^{2} [/tex]
Use the formula:[tex] {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]
[tex] {x}^{2} - 3x - 6 = {x}^{2} - 2x + 1[/tex]
Combine like terms.
[tex] {x}^{2} - {x}^{2} - 3x + 2x = 1 + 6[/tex]
[tex] - 3x + 2x = 7[/tex]
Calculate
[tex] - x = 7[/tex]
[tex]x = - 7[/tex]
Hope this helps...
Good luck on your assignment..