Answer:
Proved.
Step-by-step explanation:
The functions are:
1.) f(x) = 3x - 27 (* I am giving an answer using this equation. Perhaps you did't copy the question well!)
2.) g(x) = [tex]\frac{1}{3} x[/tex] + 9
If two functions are inverses of each other, then:
f(g(x)) = x and g(f(x)) = x situation must be satisfied.
f(g(x)) = 3([tex]\frac{1}{3}x + 9[/tex]) + 27
We simply it to get;
f(g(x)) = x - 27 + 27 = x (*This is correct)
g(f(x)) = [tex]\frac{1}{3}[/tex](3x - 27) + 9 = x - 9 + 9 = x (* This is also correct!)