y = 16-x^2
Find the value of k

Answer:
k = - 4
Step-by-step explanation:
Given
y = 16 - x²
The point (k, 0 ) is a zero. To find the zero let y = 0, that is
16 - x² = 0 ( add x² to both sides )
16 = x² ( take the square root of both sides )
x = ± [tex]\sqrt{16}[/tex] = ± 4
The zeros are x = - 4 and x = 4
Since (k, 0 ) is to the left of the origin, then k = - 4