A student takes a 48 question multiple choice quiz. The student is unprepared, so they guess on every question. The probability of guessing a correct answer is 1/4. Find the mean and standard deviation for the random variable

Respuesta :

Answer:

[tex]Mean = 12[/tex]

[tex]Standard\ Deviation = 6[/tex]

Step-by-step explanation:

Given

Number of questions, n = 48

Probability of correct answer, p = 1/4

Required

- Find the mean

- Find the standard deviation

Using probability notations;

n = 48 and p = 1/4

Mean is calculated as follows;

[tex]Mean = np[/tex]

Substitute 48 for n and 1/4 for p

[tex]Mean = 48 * \frac{1}{4}[/tex]

[tex]Mean = \frac{48}{4}[/tex]

[tex]Mean = 12[/tex]

The Mean is 12

Calculating Standard Deviation (SD)

[tex]SD = \sqrt{np(1-p)}[/tex]

Substitute 48 for n and 1/4 for p

[tex]SD = \sqrt{48 * \frac{1}{4}(1-\frac{1}{4})}[/tex]

Solve the expression in the bracket

[tex]SD = \sqrt{48 * \frac{1}{4}(\frac{4-1}{4})}[/tex]

[tex]SD = \sqrt{48 * \frac{1}{4}(\frac{3}{4})}[/tex]

Open Bracket

[tex]SD = \sqrt{48 * \frac{1}{4}*\frac{3}{4}}[/tex]

[tex]SD = \sqrt{\frac{48 * 1 * 3}{4}}[/tex]

[tex]SD = \sqrt{\frac{144}{4}}[/tex]

[tex]SD = \sqrt{36}[/tex]

Take Square Root of 36

[tex]SD = 6[/tex]

The standard deviation is 6