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Question:
The given line passes through the points (-4, -3) and (4, 1).
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-4, 3)?
a) y - 3 = -2(x + 4)
b) y - 3= - (x + 4)
c) y - 3 = (x + 4)
d) y - 3 = 2(x + 4)
Answer:
The equation of the line that is perpendicular to the given line and passes through the point (-4, 3) is
a) y - 3 = -2(x +4)
Step-by-step explanation:
First of all, we will find the slope of the given line.
We are given that the line passes through the points (-4, -3) and (4, 1)
[tex](x_1, y_1) = (-4,-3) \\\\(x_2, y_2) = (4,1) \\\\[/tex]
The slope of the equation is given by
[tex]$ m_1 = \frac{y_2 - y_1 }{x_2 - x_1} $[/tex]
[tex]m_1 = \frac{1 -(-3) }{4 -(-4)} \\\\m_1 = \frac{1 + 3 }{4 + 4} \\\\m_1 = \frac{4 }{8} \\\\m_1 = \frac{1 }{2} \\\\[/tex]
Recall that the slopes of two perpendicular lines are negative reciprocals of each other.
[tex]$ m_2 = - \frac{1}{m_1} $[/tex]
So the slope of the other line is
[tex]m_2 = - 2[/tex]
Now we can find the equation of the line that is perpendicular to the given line and passes through the point (-4, 3)
The point-slope form is given by,
[tex]y - y_1 = m(x -x_1)[/tex]
Substitute the value of slope and the given point
[tex]y - 3 = -2(x -(-4) \\\\y - 3 = -2(x +4)[/tex]
Therefore, the correct option is (a)
y - 3 = -2(x + 4)
The equation of the line in point-slope form is y - 3 = -2(x + 4)
What is a linear equation?
A linear equation is in the form:
y = mx + b
Where y,x are variables, m is the rate of change and b is the y intercept.
The line passes through the point (-4, -3) and (4, 1). Hence:
Slope = (1 - (-3)) / (4 - (-4)) = 1/2
The slope of the line perpendicular to this line is -2 (-2 * 1/2 = -1).
The line passes through (-4, 3), hence:
y - 3 = -2(x - (-4))
y - 3 = -2(x + 4)
The equation of the line in point-slope form is y - 3 = -2(x + 4)
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