Answer:
-6, -3
3, 8
Step-by-step explanation:
In order to find the number that are solutions to the compound inequalities, you first solve fr x on each inequality.
First inequality:
[tex]4(x+3)\leq 0\\\\4x+12\leq0\\\\4x\leq-12\\\\x\leq-3[/tex] interval = (-∞ , -3]
Second inequality:
[tex]x+1>3\\\\x>2[/tex] interval = (2 , ∞)
The interval solution is (-∞ , -3] U (2 , ∞)
The number that are included in the previous interval are:
-6, -3
or
3, 8
