Answer:
The gauge pressure is [tex]P = 4.2*10^{5} \ N/m^2[/tex]
Explanation:
From the question we are told that
The height of the 14th floor from the point where the water entered the building is h = 43 m
The gauge pressure is mathematically represented as
[tex]P = mgh[/tex]
Where the m is the mass of the water which is mathematically represented as
[tex]m = \frac{\rho}{V}[/tex]
Where [tex]\rho[/tex] is the density of the water which has a constant value of [tex]\rho = 1000 \ kg/m^3[/tex] and this standard value of density the volume is [tex]1 m^3[/tex] so
[tex]m = \frac{1000}{1}[/tex]
[tex]m = 1000 \ kg[/tex]
Thus
[tex]P = 1000 * 9.8 * 43[/tex]
[tex]P = 4.2*10^{5} \ N/m^2[/tex]
