Answer:
[tex]P = \frac{1}{3}[/tex]
Step-by-step explanation:
The calculation of the value of p minimizes is shown below:-
We will assume the probability of coming heads be p
p(H) = p
p(T) = 1 - P
Now, H and T are only outcomes of flipping a coin
So,
P(TTH) = (1 - P) = (1 - P) (1 - P) P
= (1 + P^2 - 2 P) P
= P^3 - 2P^2 + P
In order to less N,TTH
we need to increase P(TTH)
The equation will be
[tex]\frac{d P(TTH)}{dP} = 0[/tex]
3P^2 - 4P + 1 = 0
(3P - 1) (P - 1) = 0
P = 1 and 1 ÷ 3
For P(TTH) to be maximum
[tex]\frac{d^2 P(TTH)}{dP} < 0 for\ P\ critical\\\\\frac{d (3P^2 - 4P - 1)}{dP}[/tex]
= 6P - 4
and
(6P - 4) is negative which is for
[tex]P = \frac{1}{3}[/tex]
