The time it takes to drive from Orangeville to the Vaughan Mills Mall is normally distributed with a mean of 52 minutes and standard deviation of 5 minutes. What intervals could you estimate, using the knowledge from this activity that do not include the mean as a max or min? For example, is an interval we could estimate? However, it includes the mean as the maximum of the interval. Another example is as an example of a probability interval that we know from this activity, but it includes the mean as the minimum.

Respuesta :

Given:

Mean of 52 minutes and a standard deviation of 5 minutes.

Solution:

According to the empirical rule: For the normal distribution, all of the data will fall within three standard deviations of the mean.

1: 68% of the data will fall within the first standard deviation from the mean.

2: 95% of the data fall within two standard deviations.

3: 99.7% of the data fall within three standard deviations.

[tex]3SD =99.7\%=\mu\pm3\sigma\\[/tex]

Therefore, the 7 intervals and their probabilities are:

1. [tex]1SD=0.68=P(47<x<57)[/tex]

2. [tex]0.95=P(42<x<62)[/tex]

3. [tex]0.997=P(37<x<67)[/tex]

4.[tex]13.5\%=P(42<x<47)[/tex]

5.[tex]13.5\%=P(57<x<62)[/tex]

6. [tex]2.35\%=P(37<x<42)[/tex]

7.[tex]2.35\%=P(62<x<67)[/tex]