Answer:
Our system of equations is:
We are looking for x
Let's express y using x
Replace x in the second equation with the result
- 4y-4x²-12x = -7
- 4(-2x-1)-4x²-12x = -7
- -8x-4-4x²-12x = -7
- -8x-4x²-12x = -7+4
- -4x²-20x = -3
- -4x²-20x+3 = 0 multiply by -1 to get rid of the - signs with x
- 4x²+20x-3=0
4x²+20x+3=0 is a quadratic equation
Let Δ be our discriminant
Δ= 20²-4*4*(-3)
Δ=448 > 0 so we have two solutions for x
let x and x' be the solutions
- x = [tex]\frac{-20-\sqrt{448} }{8}[/tex]= -5.145 ≈ -5.15
- x'= [tex]\frac{-20+\sqrt{448} }{8}[/tex]= 0.145≈ 0.15
so the solutions are:
-5.15 and 0.15
