Respuesta :
Answer:
0.28
Explanation:
This allele has incomplete dominance and analysis indicated a phenotypic distribution of 600M, 4000MN, 400N.
Using p+q = 1
Where q is the frequency of the N allele-
400N/5000 = 0.08 is the genotypic frequency out of 5000 in total - q²
Thus the frequency of the allele N is √q² = √0.08 = 0.28
The frequency of the N allele is 0.48
What is incomplete dominance?
Incomplete dominance occur when a progeny of a particular parents gives or have a phenotype that combines both parents gene.
This phenotype is intermediate of the two parents and often unique.
Total population of Thailand= 5000
Allele P= 600M
Allele pq= 4000MN
Allele Q= 400N
According to hardyweingberg principles,
P+Q= 1
p2+2pq+q2=1
Therefore, to calculate frequency of allele N in the population we have;
N for Q= 400/5000=0.08
N for pq= 4000/5000=0.8
since pq contain both allele q and p in equal proportion we have
N for pq= 0.5*0.8 = 0.4
Frequency of N in allele N and MN is
0.08+ 0.4 = 0.48.
Therefore, the frequency of the N allele is 0.48
Learn more on incomplete dominance here,
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