Answer:
[tex]T=1235K=962\°C[/tex]
Explanation:
Hello,
In this case, from thermodynamics, it is widely known that the entropy of fusion is defined in terms of the enthalpy of fusion at the fusion temperature (melting point) as shown below:
[tex]\Delta _fS=\frac{\Delta _fH}{T}[/tex]
Thus, solving for the melting point:
[tex]T=\frac{\Delta _fH}{\Delta _fS}[/tex]
Hence, for silver:
[tex]T=\frac{11.30kJ/(mol)*\frac{1000J}{1kJ} }{9.150J/(mol*K)} \\\\T=1235K=962\°C[/tex]
Which is a typical high temperature for a metal such as silver.
Best regards.
