bunny220
contestada

What is the internal energy of 3.00 mol of N2 gas at 25°C? To solve this
5
problem, use the equation: U diatomic gas
Remember that R = 8.31 J/(mol-K) and K = °C + 273.
= nRT
A.1560j
B.37,100j
C.623j
D.18,600j

Respuesta :

Answer:

E = 18,600 J

Explanation:

It is given that,

Number of moles = 3

Temperature, T = 25°C = 25+273 = 298 K

The internal energy of N₂ gas is given by :

[tex]U=f\times nRT[/tex]

f is degrees of freedom. For diatomic gas, degree of freedom is equal to 5/2. So,

[tex]U=\dfrac{5}{2}\times 3\times 8.31\times 298\\\\U=18572.85\ J[/tex]

or

U = 18600 J

So, the internal energy of the gas is 18,600 J