What is the equation of the following line written in slope-intercept form?

Answer:
[tex] y = 5x [/tex]
Step-by-step explanation:
Line equation is given as y = mx + b
Where, m is the slope of the line, which is,
[tex] m = \frac{y2 - y1}{x2 - x1} [/tex]
b is the y-intercept. It is the point at which the line crosses the y-axis for which the value of x = 0.
=>Find m and b to derive an equation for the line.
using the 2 coordinate pairs, (1, 5), (-1, -5),
Let, x2 = -1,
x1 = 1,
y2 = -5,
y1 = 5
[tex] m = \frac{y2 - y1}{x2 - x1} [/tex]
[tex] m = \frac{-5 - 5}{-1 - 1} [/tex]
[tex] m = \frac{-10}{-2} [/tex]
[tex] m = 5 [/tex]
From the graph given, the line intercepts the y-axis at point 0. Therefore b = 0.
Plug in the values of m and b in the line of equation.
y = mx + b
y = 5x + 0
y = 5x
Therefore, the equation of the line, in the graph above, written in slope-intercept form is:
[tex] y = 5x [/tex]