Step-by-step explanation:
[tex]\dfrac{w}{3}<1\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup\cdot\dfrac{w}{3\!\!\!\!\diagup}<3\cdot1\\\\w<3\\===========================\\3w+5>11\qquad\text{subtract 5 from both sides}\\\\3w+5-5>11-5\\\\3w>6\qquad\text{divide both sides by 3}\\\\\dfrac{3w}{3}>\dfrac{6}{3}\\\\w>2\\\\[/tex]
[tex]\text{If is}\ \bold{OR},\ \text{then}:\\\\w<3\ or\ w>2\Rightarrow w\in\mathbb{R}\ /\text{any real number/}\\\\\text{If there is a mistake, and it should be}\ \bold{AND},\ \text{then}:\\\\w<3\ and\ w>2\Rightarrow 2<w<3\to w\in(2;\ 3)[/tex]
