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A television station claims that the amount of advertising per hour of broadcast time has an average of 16 minutes and a standard deviation equal to 1.4 minutes. You watch the station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 8 minutes. Calculate the z-score for this amount of advertising time. Group of answer choices

Respuesta :

Answer:

-4.29

Step-by-step explanation:

The computation of the z score is shown below:

data provided in the question

Average minutes = 16 minutes

Standard deviation = 1.4 minutes

Amount of advertising time = 8 minutes

Based on the above information, the z score is

[tex]= \frac{x-m}{\sigma} \\\\ = \frac{8-14}{\1.4} \\\\ = \frac{-6}{1.4}[/tex]

= -4.29

Hence, the z score is -4.29. It is come by considering the above formula

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