Answer:
THE AMOUNT OF HEAT ABSORBED DURING THE REACTION IS 151.64 JOULES
Explanation:
Mass = 12.58 g
Specific heat of CaCO3 = 0.82 J/g K
Change in temperature = 38.3 C - 23.6 C = 14.7 C
How many joules of heat are absorbed?
Heat of a reaction is the amount of heat absorbed or evolved when a gram of a sample is raised by 1 C.
Heat = mass * specific heat * change in temperature
Heat = 12.58 * 0.82 * 14.7
Heat = 151.64 J
The amount of joules absorbed during this reaction is 151.64 J.
