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Answer:
The third one.
Step-by-step explanation:
The last bar graph is skewed to the right, since the values of its fourth and fifth bars are way smaller than the values of its first, second, and third graphs. The drastically smaller values pull down the mean of the last bar graph, making it be more different from the median.
Comparatively, bar graphs one and two have approximately symmetrical distributions of numbers on both sides of the central bar. This means that their mean is balanced out on both sides and that neither of them is significantly skewed left or right.
A bar graph. The horizontal axis is unnumbered. The vertical axis is numbered 0 to 50. The first bar is 38. The second bar is 43. The third bar is 21. The fourth bar is 5. The fifth bar is 1 is data distribution would most likely have a mean and median that are not close in value.
We have to determine, which data distribution would most likely have a mean and median that are not close in value.
According to the question,
The mean and the median both reflect the skewing, but the mean reflects it more.
The last bar graph is skewed to the right since the values of its fourth and fifth bars are way smaller than the values of its first, second, and third graphs.
The drastically smaller values pull down the mean of the last bar graph, making it be more different from the median.
The mean and the median are the same. This example has one mode (unimodal), and the mode is the same as the mean and median.
Bar graphs one and two have approximately symmetrical distributions on both sides of the central bar.
This means that their mean is balanced out on both sides and that neither of them is significantly skewed left or right.
Hence, The horizontal axis is unnumbered. The vertical axis is numbered 0 to 50. The first bar is 38. The second bar is 43. The third bar is 21. The fourth bar is 5. The fifth bar is 1.
To know more about Probability click the link given below.
https://brainly.com/question/23044118
