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A box is dragged across a floor by pulling on a rope attached to the crate and inclined 25 o above the horizontal. If the coefficient of static friction is 0.64, it requires a force of 350 N to just start it moving. What is the mass of the box

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whitneytr12

Answer:

[tex]m=35.58 kg[/tex]

Explanation:

Using the first Newton's equation

[tex]\Sum F_{T}=F-mgsin(25)-\mu mgcos(25)=0[/tex]

We just need to solve it for m:

[tex]m=\frac{F}{g(sin(25)+\mu cos(25))}[/tex]

[tex]m=\frac{350}{9.81(sin(25)+0.64cos(25))}[/tex]

[tex]m=35.58 kg[/tex]

I hope it helps you!

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