Answer:
[tex]F=9.06*10^{-8} N[/tex]
Explanation:
We can use the Coulomb force
[tex]F=k\frac{q_{e}q_{p}}{r^{2}}[/tex]
[tex]F=9*10^{9}\frac{|-(1.6*10^{-19})^{2}|}{(5.29*10^{11})^{2}}[/tex]
[tex]F=9.06*10^{-8} N[/tex]
The direction of the force is toward proton with respect to the electron reference coordinate and is in the direction of the electron in the proton system reference.
I hope it helps you!
