Respuesta :
Answer:
number of moles of CO2 is 0.054
number of moles of CO is 0.107
number of moles of O2 remaining is 0.01 mole
mole fraction of CO is 0.63
Explanation:
Firstly, we write the equation of reaction;
3C(s) +2O2(g) → CO2(g) +2CO(g)
Now, we proceed.
From the written equation, we can deduce that
3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO
No of mol of C reacted = 0.161 mol
limiting reactant according to the question is Carbon
a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)
b. no of mol of CO formed = 0.161*2/3 = 0.107 mol
c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole
d. mole fraction of CO = no of mol of CO/Total number of moles
= 0.107/(0.107+0.054+0.01)
= 0.625730994152 which is approximately 0.63
The number of moles of CO₂, CO, and O₂ formed is 0.054, 0.107, and 0.01 mole respectively.
And the mole fraction of CO is 0.63
Number of moles and Mole fraction:
The equation of reaction is given as the following:
3C(s) +2O₂(g) → CO₂(g) +2CO(g)
from above we can say that the number of moles required for the reaction to proceed is:
3 mol of C
2 mol of O₂
1 mol CO₂, and
2 mol CO
so the ratio is:
C:O₂:CO₂:CO = 3:2:1:2
Given that the number of mol of C produced is 0.161 mol
(i) number of mol of CO₂ formed = 0.161 × 1/3 = 0.054 moles
(ii) number of mol of CO formed = 0.161 × 2/3 = 0.107 mol
(iii) number of mol of O₂ remaining = 0.117 - (0.151 × 2/3)
= 0.117 - 0.107
= 0.01 mole
(iv) mole fraction of CO = (number of mol of CO) / (Total number of moles)
= 0.107 / (0.107+0.054+0.01)
= 0.63
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