Respuesta :
Answer:
0.08
Explanation:
this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.
The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this
t = 2d/v
t = 2*58.8/1520
t = 117.6/1520
t = 0.077368 s
t ≈ 0.08 s (less then 1 s)
Answer:
0.0774s
Explanation:
The formula to find the time of an echo is time = (2)(distance) / (velocity)
So plug in the numbers to the formula
(2)(58.8) / (1520)
= 0.0774s