Answer:
Step-by-step explanation:
Displacement vector R = 2i + j + 3k
Unit vector along displacement vector
= R / I R I
= ( 2i + j + 3k ) / √ ( 2² + 1² + 3² )
= ( 2i + j + 3k ) / √ 14
Now force F acts in the direction of this unit vector . It is magnitude of 20 N
So this vector can be represented by the following expression
F = 20 [ ( 2i + j + 3k ) / √ 14 ]
[tex]F= \frac{20}{\sqrt{14} } \times ( 2i+j+3k)[/tex]
