Calculate the number of ATP generated from one saturated 10 ‑carbon fatty acid. Assume that each NADH molecule generates 2.5 ATP and that each FADH2 molecule generates 1.5 ATP .

Respuesta :

Answer:

Total ATP molecules produced = 66 molecules of ATP

Explanation:

A 10-carbon fatty acid when it has undergone complete oxidation will yield 5 acetyl-CoA molecules and 4 FADH₂ and 4 NADH molecules each. Each of the 5 acetyl-CoA molecules enters into the citric acid cycle and is completely oxidized to yield further ATP and  FADH₂ and NADH molecules.

The total yield of ATP in the various enzymatic step is calculated below:

Acyl-CoA dehydrodenase = 4 FADH₂

β-Hydroxyacyl-CoA dehydrogenase = 4 NADH

Isocitrate dehydrogenase = 5 NADH

α-Ketoglutarate dehydrogenase = 5 NADH

Succinyl-CoA synthase = 5 ATP (from substrate-level phosphorylation of GDP)

Succinate dehydrogenase = 5 FADH₂

Malate dehydrogenase = 5 NADH

Total ATP  from FADH₂ molecoles = 9 * 1.5 = 13.5

Total NADH molecules = 19 * 2.5 = 47.5

Total ATP molecules produced = 13.5 + 47.5 + 5

Total ATP molecules produced = 66 molecules of ATP

Answer:

  • Number of ATP generated = = [tex]64 ATPs[/tex]

Explanation:

First, calculate the number of acetyl-CoA molecules formed:

Number of acetyl-CoA molecules = [tex]\frac{number of carbons in fatty acid}{2}[/tex]

[tex]= \frac{10}{2}\\\\ = 5 acetyl-CoA molecules[/tex]

Next, calculate the number of rounds of beta-oxidation:

Number of rounds = number of acetyl-CoA molecules - 1

[tex]= 5 - 1\\\\ = 4 rounds[/tex]

Calculate the number of ATP from NADH and FADH2:

If each NADH yields 2.5 ATPs and each FADH2 yields 1.5 ATPs, then multiply the number of rounds by 4 and multiply the number of acetyl-CoA molecules by 10.

[tex](4 * 4) + (5 * 10) = 66 ATP[/tex]

Subract two ATP molecules for activation of the fatty acid.

[tex]Total ATP = 66 - 2\\\\ = 64 ATPs[/tex]

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