Answer:
24.1 m/s
Explanation:
Work = change in KE = [tex]KE_{f} - KE_{i}[/tex]
KE initial is 0 because the initial velocity is 0. Therefore, work is equal to final kinetic energy. With that:
[tex]W = KE_{f} = \frac{1}{2}mv_{f}^{2}[/tex]
With some algebraic manipulations,
[tex]v_{f} = \sqrt{\frac{2W}{m} } = \sqrt{\frac{2*450000 J}{1550 kg} } = 24.1 m/s[/tex]
