HURRY I NEED IT NOW!!! What is the solution to this system of equations? x + 2 y = 4. 2 x minus 2 y = 5. (3, Negative 5 and one-half) (3, one-half) no solution infinitely many solutions

Respuesta :

Answer:

(3, 1/2)

Step-by-step explanation:

set the equation up

x+2y=4

2x-2y=5

then solve

The correct option is B.[tex](3,\frac{1}{2})[/tex]

Given equations,

[tex]x+2y=4.....(1)\\2x-2y=5.....(2)[/tex]

The standard form for linear equations in two variables is [tex]Ax+By=C[/tex].

On comparing equation 1 and equation 2 with the standard form we get,

[tex]a_{1}=1, b_{1}=2, c_{1}=4\\a_{2}=2, b_{2}=-2,c_{2}=5[/tex]

Here,

[tex]\frac{a_{1} }{a_{2} } =\frac{1}{2} \\[/tex] and [tex]\frac{b_{1} }{b_{2} } =\frac{2}{-2} =-1[/tex]

Since [tex]\frac{a_{1} }{a_{2} } \neq \frac{b_{1} }{b_{2} }[/tex], So the given system of equation has a unique solution.

Now Adding equation 1 and 2 we get,

[tex]3x=9\\x=3[/tex]

putting the value of x in equation 1 we get,

[tex]3+2y=4\\2y=1\\y=\frac{1}{2}[/tex].

Hence the required solution of equation is [tex](3,\frac{1}{2})[/tex]. the correct option is B.[tex](3,\frac{1}{2})[/tex]

For more details follow the link:

https://brainly.com/question/11897796