Find the first, fourth, and eighth terms of the sequence A(n)=-3 X 2^n-1

1; –216; –279,936

–6; –48; –768

–12; –96; –1,536

–3; –24; –384

Respuesta :

Answer:

The answer is

3, 24, 384

Step-by-step explanation:

Usng the formula

[tex]A(n) = 3(2) ^{n - 1} [/tex]

Where n is the number of terms

For the first term

[tex]A(1) = 3(2)^{1 - 1} \\ = 3(2) ^{0} \\ = 3(1) \\ \\ = 3[/tex]

For the fourth term

[tex]A(4) = 3(2)^{4 - 1} \\ = 3 ({2})^{3} \\ = 3 \times 8 \\ \\ = 24[/tex]

For the eighth term

[tex]A(8) = 3 ({2})^{8 - 1} \\ = 3 ({2})^{7} \\ = 3(128) \\ \\ = 384[/tex]

Hope this helps you

Answer: –3; –24; –384

Step-by-step explanation: