Two 15-Ω and three 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes through each bulb?

Before we determine the amount of current in each bulb, we must first know that the same current flows in a series connected resistors. Since the Two 15-Ω and three 25-Ω light bulbs are connected in series, same current will flow in all of them.

According to Ohm's law, E = IRt where;

E is the supply voltage = 24V

I is the total current flowing in the circuit

Rt is the total equivalent resistance.

First, we need to calculate Rt.

Rt = 15Ω+15Ω+25Ω+25Ω+25Ω (Two 15-Ω and three 25-Ω light bulb in series)

Rt = 105Ω

From ohms law formula, I = E/Rt

I = 24/105

I = 0.229Amp

Since the total current in the circuit is 0.229A, therefore the amount of current that passes through each bulb is the same as the total current i.e 0.229A

andromache andromache · Answer 2 · 2022-03-03T15:32:47+01:00

The current that passes via each bulb is 0.229A

Ohm law:

According to the above law,

E = IRt

Here

E should be the supply voltage = 24V

I should be the total current flowing in the circuit

Rt should be the total equivalent resistance.

Now Rt should be

Rt = 15Ω+15Ω+25Ω+25Ω+25Ω

Rt = 105Ω

Now the current is

I = E/Rt

I = 24/105

I = 0.229Amp

Therefore, The current that passes via each bulb is 0.229A.

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