Answer:
x= -5, -1
Step-by-step explanation:
To find the zeroes of a function,
First expand the terms to get the form [tex]ax^{2} + bx +c[/tex] where 'a, b, and c' are constants
[tex]f(x)= (x+3)^{2} -4[/tex]
[tex]f(x)= x^{2}+6x+9-4[/tex]
[tex]f(x)= x^{2} +6x +5[/tex]
Now, factor the equation
This can be done using the quadratic formula or other methods
One simple method is to find the two values that would get:
A good way to verify is to expand the terms and make sure the function looks the same
In this case, the equation can broken into
f(x)= (x+1)*(x+5)
Now, look at each term individually and set each of them to equal 0
x+1 =0
x+5=0
Solve for x in each case
x= -1
x= -5
Now, ordering them from least to greatest would be: x= -5, -1
