If a(x) = 3x + 1 and b(x) = sqrt x-4 what is the domain of (b•a)(x)

Answer:
[4, infinity)
Step-by-step explanation:
(b·a)(x) = (sqrt(x - 4)·(3x + 1). The domain of 3x + 1 is "all real numbers," but the presence of the sqrt function limits the input to (b·a)(x) to [4, infinity); recall that the argument of the sqrt function must be zero or greater.