Respuesta :
There are 108 integers with 4-digits that are evenly divisible by 5.
Answer:
100
Step-by-step explanation:
If a number is divisible by 5, then the last digit is either 0 or 5.
Since all the digits are even, the last digit must be 0.
There are 4 options for the first digit (2, 4, 6, 8).
There are 5 options for the second digit (0, 2, 4, 6, 8).
There are 5 options for the third digit (0, 2, 4, 6, 8).
So the total number of numbers is:
4×5×5×1 = 100