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A long, rigid conductor, lying along an x axis, carries a current of 5.0 A in the negative x direction. A magnetic field B: is present, given by B: ???? 3.0iˆ ???? 8.0x2jˆ, with x in meters and B: in milliteslas. Find, in unit-vector notation, the force on the

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Answer:

Explanation:

magnetic field B = (3 i + 8 x 2 j )x 10⁻³ T

= (3 i + 16 j )x 10⁻³ T

L = - i ( unit length of conductor )

Force F = I ( L x B ) , I is current

= 5 [ - i x ( 3i + 16 j ) 10⁻³]

= 5 ( - 16 k ) x 10⁻³

F = - 80 x 10⁻³ k

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