Answer: 0.002174
Explanation:
Given that the
Yield strength rho = 450 MPa
Length = 2 m
Elastic modulus E= 207 GPa
According to Hook's law, if the elastic limits is not reached, the elastic modulus is the ratio of elastic strength to the elastic strain ə
E = rho/ə
Make ə the subject of formula
ə = rho/ E
ə = (450 × 10^6) / (207 × 10^9)
ə = 2.174 × 10^-3
Therefore, the engineering strain which depends on engineering stress and elastic modulus is 2.174 × 10^-3
Elastic Strain has no S.I Units.
