Answer:
V = 3t² - 12 (velocity as function of t)
a = 6t (acceleration as function of t)
Explanation:
The distance covered by an object is given as a function of time :
s = t³ - 12t
where,
s = distance
t = time
Since, velocity is given as:
V = ds/dt
V = d/dt(t³ - 12t)
Applying derivative:
V = 3t² - 12 (velocity as function of t)
Since, acceleration is given as:
a = dV/dt
a = d/dt(3t² - 12)
Applying derivative:
a = 6t (acceleration as function of t)
