The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium concentration of FeSCN2

Respuesta :

Answer:

The concentration is [tex]C = 1.11 mol/L[/tex]

Explanation:

From the question we are told that

     The absorbance is  [tex]A = 0.347[/tex]

       The length is  [tex]l = 447 nm = 447 *10^{-7} \ cm[/tex]

     

Generally absorbance is mathematically represented as

        [tex]A = \epsilon* C * l[/tex]

where [tex]\epsilon[/tex] is the molar absorptivity of  FeSCN2  with a value [tex]\epsilon = 7.0*10^3 L/cm/mol[/tex]

 and  [tex]C[/tex] is the equilibrium concentration of FeSCN2

So  

       [tex]C = \frac{A}{\epsilon * l }[/tex]

substituting values

        [tex]C = \frac{0.347}{7.0*10^{3} * 447 *10^{-7} }[/tex]

         [tex]C = 1.11 mol/L[/tex]